-16x^2+1326=0

Solution for -16x^2+1326=0 equation:

-16x^2+1326=0

a = -16; b = 0; c = +1326;
Δ = b2-4ac
Δ = 02-4·(-16)·1326
Δ = 84864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{84864}=\sqrt{64*1326}=\sqrt{64}*\sqrt{1326}=8\sqrt{1326}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{1326}}{2*-16}=\frac{0-8\sqrt{1326}}{-32}
=-\frac{8\sqrt{1326}}{-32}
=-\frac{\sqrt{1326}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{1326}}{2*-16}=\frac{0+8\sqrt{1326}}{-32}
=\frac{8\sqrt{1326}}{-32}
=\frac{\sqrt{1326}}{-4}
$